Sometimes I’ve found it hard to determine certain formulas for Cisco QoS calcuations due to the vast number of documents regarding a certain subset of the large QoS topic. For the CCIE Voice Lab it is important to understand Cat 6500 QoS. Within this topic are policers which are made up of either aggregate or microflow. Part of the aggregate policer configuration is determining the “burst” value. The best explaination I have found is here.
For example, if you want to calculate the minimum burst value needed to sustain a rate of 1 Mbps on an Ethernet network, the rate is defined as 1 Mbps and the maximum Ethernet packet size is 1518 bytes. The equation is:
The larger result is 12144, which you round to 13 kbps.